Question

PQ is a chord of a circle and R is a point on the minor arc. If PT is a tangent at a point P such that angleQPT = 60 degrees. Then find anglePRQ.

Answer 1

Given, PQ is a chord of a circle with center O. Also, ∠QPT = 60°.

let x be the point on the tangent PT.

Now, ∠QPT + ∠QPX = 180°  [Linear pair]

⇒ ∠QPX = 180° - ∠QPT = 180° - 60° = 120°

Again, ∠QPX = ∠PRQ  [Alternate segment theorem]

⇒ ∠PRQ = 120°

pls mark as brainliest pls.....