Question

PQ IS A CHORD OF A CIRCLE AND R IS POINT ON THE MINOR ARC .IF PT IS A TANGENT AT POINT P SUCH THAT ANGLE QPT IS 60DEGREE THEN FIND ANGLE PRQ

Answer 1

Given, PQ is a chord of a circle with center O. Also, ∠QPT = 60°.

let x be the point on the tangent PT.

Now, ∠QPT + ∠QPX = 180° [Linear pair]

⇒ ∠QPX = 180° - ∠QPT = 180° - 60° = 120°

Again, ∠QPX = ∠PRQ [Alternate segment theorem]

⇒ ∠PRQ = 120°

Hope u got ur answer have a nice day ☺️