Math, asked by sandhyasarkar9450595, 6 months ago

PQ is a chord of a circle. The length of PQ is 24 cm.
R is the mid-point of PQ. Perpendicular from Ron
either side of the chord PQ meets the circle at M and
N respectively. If RN > RM and RM = 6 cm, then the
length of RN is​

Answers

Answered by dnavu10
0

Answer:

24 cm

Step-by-step explanation:

Attachments:
Answered by amitnrw
0

Given : PQ is the chord of the circle the length of PQ is 24 cm .R is the mid point of PQ. perpendicular from R on either side of the chord PQ meets the circle at M and N respectively

RM=6 cm

To Find :  Length of RN

Solution:

PQ = 24 cm

R is mid point of PQ

=> PR = QR  = PQ/2

=> PR =QR = 24/2

=> PR = QR = 12 cm

RM = 6 cm

RN = ?

MN is chord as perpendicular from R on either side of the chord PQ meets the circle at M and N respectively.

chord theorem  : products of the lengths of the line segments on each chord are equal

RN x RM = PR x QR

=> RN x 6  = 12 x 12

=> RN = 24 cm

Additional info MN is diameter hence 24 + 6 = 30 cm is diameter of circle

Learn More:

The radius of chords are equal .this chord intersect at a point on ...

https://brainly.in/question/14976739

Let O be the centre of a circle and AC be its diameter. BD is a chord ...

https://brainly.in/question/13796690

Similar questions