Question

PQ is a chord of a circle with centre O and PT is a tangent at P such that angle QPT=60 degree. then, angle PRQ=?

Answer 1

where is R in your question

Answer 2

∠PRQ = 120 degree

Step-by-step explanation:

given data

chord = PQ

centre = O

tangent = P

QPT = 60 degree

solution

we know here PT is a tangent

so that here ∠OPT will be = 90 degree

so here sum of triangle is 180 degree

∠OPQ + ∠OQP + ∠ POQ = 180   .................1

here

∠OPQ = ∠OPT - ∠QPT

so put value

∠OPQ = 90 - 60 = 30

now put value in equation 1 we get ∠POQ

∠POQ = 180 - 30 - 30

∠POQ = 120 degree

then

∠ PRQ = $\frac{1}{2}$ reflex angle  ∠POQ.

so here

∠PRQ will be

∠PRQ = $\frac{1}{2}$  ×  (360 - 120)  

∠PRQ = 120 degree

Learn more :

PQ is a chord of a circle with

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