PQ is a chord of circle the tangent XR draws at X meets PQ at R when produced if XR=12 cm , PQ=X cm , QR=(X-2) cm then X=______cm
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Step-by-step explanation:
RX is a tangent and PQ is a chord of the circle.
Now, RX²=RQ×PR
12²=(x−2)(x+x−2)
144=(x−2)(2x−2)
144=2x²−2x−4x+4
2x²-6x−140=0
x²−3x−70=0
x²+7x−10x−70=0
(x−10)(x+7)=0
x=−7,10
x cannot be negative. Hence, x=10
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