Question

PQ is a chord of length 4.8 cm of a
circle of radius 3 cm. The tangents at P
and Q intersect at a point T as shown
in the figure. Find the length of TP.
[CBSE 2013C]​

Answer 1

Step-by-step explanation:

PQ chord length = 4.8cm

radius always bisects chords in equal parts this implies.

Angle OTP = Angle OTQ = 90°

OP = OQ = radius of circle.

=> Angle OPT = Angle OQT

( Because it become isosceles triangle)

OT = OT ( because it's common)

So, triangle OTP is congruent to triangle OTQ by Right Angled Triangle. (RHS)

Then,

PT = TQ

PQ = PT + TQ = 2 PT = 2 TQ = 4.8cm

=> PT = TQ = 4.8/2 = 2.4 cm.

Here your answer budd. Best of Luck