PQ is a chord of length 8 cm of a circle of radius 5 cm. The tangents at P and Q intersect at point T. Find the length of TP.
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this is 1st part and 2nd part is
By equating equation 1 and 2
20+x^2+6x=x^2+10x
20=4x
x=5 cm
So,
TP=_/x^2+10x
= _/25+50
=5_/3 cm
By equating equation 1 and 2
20+x^2+6x=x^2+10x
20=4x
x=5 cm
So,
TP=_/x^2+10x
= _/25+50
=5_/3 cm
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