Question

PQ is a chord of length 8 cm of a circle of radius 5 cm. The tangents at P and Q intersect at a point T. Find the length of TP.

Answer 1

Answer:

TP= 20/3 cm

Step-by-step explanation:

Let TR=y

Since OT is perpendicular bisector of PQ.

Therefore, PR-QR-4cm

In right triangle OTP and PTR, we have,

TP²-TR²+PR²

Also, OT²-TP²+OP²

OT²=(TR²+PR²) + Op²

(y+3)²-y²+16+25 (OR = 3, as OR² = OP²-PR²)

= 6у=32

= y = 16/3= TP²

=TR²+PR²= TP²

= (16/3)²+4²=256/9+16=400/9

= TP= 20/3 cm

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