Question

pq is a chord of length 8 cm of a circle of radius 5cm

Answer 1

Answer:

The chord PQ is at a distance of 3 cm from the centre of the circle

Step-by-step explanation:

Concept used:

The perpendicular which drawn from centre of a circle to a chord bisects the chord .

Let O be the centre of the circle.

Drraw OR ⊥ PQ

Then, PR=QR= 4 cm

In right triangle ORQ,

By puythagors theorem,

$OR^2+QR^2=OQ^2$

$OR^2+4^2=5^2$

$OR^2+16=25$

$OR^2=25-16$

$OR^2=9$

$OR=\sqrt9$

$OR=3\:cm$

Therefore, the chord PQ is at a distance of 3 cm from the centre of the circle.

Answer 2

Answer:

distance of chord from Center = 3 cm

Step-by-step explanation:

Pq is a chord of length 8 cm of a circle of radius 5cm

We need to find distance of chord from Center

Let say Center = O

we draw ⊥ OD at PQ

⊥ at chord bisects the chord

=> PD = PQ/2 = 8/2 = 4 cm

OP = 5 cm (radius)

In Δ ODP

using Pythagoras theorem

OP² = PD² + OD²

=> 5² = 4² + OD²

=> OD² = 25 - 16

=> OD² = 9

=> OD = 3

distance of chord from Center = 3 cm