PQ is a chord of length 8cm of a circle of radius 5cm. The tangent at P and Q intersect at a point T. Find the length TP?
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Check Diagram too ^_^
We have a circle of radius 5 cm with a chord of length 8 cm.
We have to find length TP.
|_POM = (/) qita
We have,
OP=5 cm
PM=4 cm .......(perpendicular from the centre divides the chord)
OM=3 cm .......(by using Pythagorean triplet)
Let and TP be x.
Use trigonometric ratio in the triangle PMO and POT we get,
(diagram 2 ( for equation))
Therefore, TP=6.66 cm
Hope it helps you (^^)
Thanks,(^^)^_^
We have a circle of radius 5 cm with a chord of length 8 cm.
We have to find length TP.
|_POM = (/) qita
We have,
OP=5 cm
PM=4 cm .......(perpendicular from the centre divides the chord)
OM=3 cm .......(by using Pythagorean triplet)
Let and TP be x.
Use trigonometric ratio in the triangle PMO and POT we get,
(diagram 2 ( for equation))
Therefore, TP=6.66 cm
Hope it helps you (^^)
Thanks,(^^)^_^
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