Question

PQ is a current carrying conductor in the plane of the paper as shown in the

figure below.

(i) Find the directions of the magnetic fields produced by it at points R and S?

(ii) Given r1> r2, where will the strength of the magnetic field be larger? Give
reasons.

(iii) If the polarity of the battery connected to the wire is reversed, how would

the direction of the magnetic field be changed?

(iv) Explain the rule that is used to find the direction of the magnetic field for a

straight current carrying conductor.​

Answer 1

Explanation:

Answer is there on Marking Scheme of Sample Paper

Check from there..

Answer 2

Answer:

(i) The magnetic field lines produced is into the plane of the paper

at R and out of it at S.

(ii) Field at S > Field at P

Magnetic field strength for a straight current carrying

conductor is inversely proportional to the distance from the

wire.

(iii) The current will be going from top to bottom in the wire shown

and the magnetic field lines are now in the clockwise direction

on the plane which is perpendicular to the wire carrying

current.

(iv) Right hand thumb rule. The thumb is aligned to the direction

of the current and the direction in which the fingers are

wrapped around the wire will give the direction of the

magnetic field.