Question

PQ is a line segment and line m is a perpendicular bisector if a point A lies on m show that A is equidistant from P and Q

Answer 1

Answer:

Given :-

AB is a line segment,

L is drawn perpendicular to AB

A point p lies on line L.

(Also, Shown in figure! Refers to attachment)

To Prove :

• P is equidistant from A and B.

Solution :-

In ∆AOP and ∆BOP ,

OP = OP ( common side )

POA = POB

AO = OB

∆AOP ∆BOP (By S.A.S.)

=> AP = BP ( By C.P.C.T. )

Hence, P is equidistant from A and B .

Thus Proved :)

Answer 2

Answer:AB is a line segment,

L is drawn perpendicular to AB

A point p lies on line L.

Step-by-step explanation:

In ∆AOP and ∆BOP ,

OP = OP ( common side )

POA = POB

AO = OB

∆AOP ∆BOP (By S.A.S.)

=> AP = BP ( By C.P.C.T. )

Hence, P is equidistant from A and B .

Thus Proved