PQ is a line segment and line 'm' is its perpendicular bisector,if a point A lies on 'm',show that A is equidistant from P and Q. PLZ ANSWER FAST
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Given :-
AB is a line segment,
L is drawn perpendicular to AB
A point p lies on line L.
(Also, Shown in figure! Refers to attachment)
To Prove :
• P is equidistant from A and B.
Solution :-
In ∆AOP and ∆BOP ,
OP = OP ( common side )
POA = POB
AO = OB
∆AOP ∆BOP (By S.A.S.)
=> AP = BP ( By C.P.C.T. )
Hence, P is equidistant from A and B .
Thus Proved :)
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