Question

PQ is a straight line of 13 units.If P has the co-ordinates (5,-3) and Q has the co-ordinates (-7,y); find the values of 'y'.​

Answer 1

Answer:

Step-by-step explanation:

What does the vertical axis represent on an acceleration graph?

The vertical axis represents the acceleration of the object.

For example, if you read the value of the graph shown below at a particular time, you will get the acceleration of the object in meters per second squared for that moment.

Try sliding the dot horizontally on the graph below to choose different times, and see how the acceleration—abbreviated Acc—changes.

 

 

Concept check: According to the graph above, what is the acceleration at time t=4\text{ s}t=4 st, equals, 4, start text, space, s, end text? [Show me the answer.]

t=4\text{ s}t, equals, 4, start text, space, s, end text+1\dfrac{\text m}{\text s^2}  

 

plus, 1, start fraction, start text, m, end text, divided by, start text, s, end text, squared, end fractiont=4\text{ s}t, equals, 4, start text, space, s, end text+1\dfrac{\text m}{\text s^2}  

 

Answer 2

Answer:

Step-by-step explanation:

Distance Formula will be used

P(5,-3) and q(-7,y)

Distance PQ = $\sqrt{(5-(-7))^2+(-3+y)^2}$

13 = $\sqrt{12^2+3^2-6y+y^2}$

$13^{2}$ = 144 + 9 + $y^{2}$ - 6y

169 - 153 = $y^{2}$ - 6y

16 = $y^{2}$ - 6y

0 = $y^{2}$ - 6y - 16

Factorizing the above equation

$y^{2}$- 8y + 2y - 16

y (y-8) +2 (y-8)

(y-8) (y+2)

Y = 8 or Y = -2