PQ is a straight line of 13 units. If P has the coordinates (5,-3) and Q has the coordinates (-7,y) find the value of y
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Answered by
14
use slope formula, after that put the values in the variables and you may get your answer
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Answered by
86
here your answer .
step by step explanation.
given, PQ = 13 units
here we, apply distance formula
PQ = √(X2-X1)² + (y2-y1)²
squaring on both side.
PQ²=(X2-X1)² + (Y2-Y1)²
13² = (-7 - 5)² + (y- -3)²
169= 144 + y²+9-6y
y²+9-6y + 144 - 169 = 0
y²-6y-16 = 0
y²-8y+2y-16 = 0
y(y-8)+2(y-8)
(y-8) (y+2)
y = 8 or y = -2
i hope it will helps you.
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