pq is a straight line of 13 units length if p has coordinates (2,5) and q has the co- ordinates (x,-7) ,then the value of x is ?
Answers
Answered by
3
PQ = 13
Apply distance formula
PQ = √(X2-X1)² + (Y2-Y1)²
squaring both sides
PQ² = (X2-X1)² + (Y2-Y1)²
(13)² = (x - 2)² + (-7 - 5 )²
169 = x²+4-4x + 144
x²+4-4x+144-169 = 0
x² -4x -21 = 0
x²-7x+3x-21 = 0
x(x-7)+3(x-7) = 0
(x-7)(x+3) = 0
x = 7. OR. x = -3
Apply distance formula
PQ = √(X2-X1)² + (Y2-Y1)²
squaring both sides
PQ² = (X2-X1)² + (Y2-Y1)²
(13)² = (x - 2)² + (-7 - 5 )²
169 = x²+4-4x + 144
x²+4-4x+144-169 = 0
x² -4x -21 = 0
x²-7x+3x-21 = 0
x(x-7)+3(x-7) = 0
(x-7)(x+3) = 0
x = 7. OR. x = -3
neeleshdhakad8415:
thanks
Similar questions