PQ is a tangent at a point C to a circle with center O. If AB is a diameter and angleCAB is 30 degree find anglePCA
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according to this question
OA=OC( radius of circle)
angleOAC=angleOCA
then angleOCA =30
we know that radius is always perpendicular to tangent then
angkePCO =90
anglePCA+angleOCA=90
anglePCA+30=90
anglePCA= 60
OA=OC( radius of circle)
angleOAC=angleOCA
then angleOCA =30
we know that radius is always perpendicular to tangent then
angkePCO =90
anglePCA+angleOCA=90
anglePCA+30=90
anglePCA= 60
anki93080:
draw the figure
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