Question

PQ IS A TANGENT AT Q TO A CIRCLE WHOSE CENTRE IS O AND DIAMETER IS QR. IF ANGLE PQR IS 120°, THEN FIND ANGLE OPQ​

Answer 1

Step-by-step explanation:

∠QOP + ∠POR = 180°∠QOP + 120° = 180°∠QOP = 180° - 120°∠QOP = 60°In ΔPOQ∠QOP + ∠OPQ + ∠PQO = 180°60° + ∠OPQ + 90° = 180°150° + ∠OPQ = 180°∠OPQ = 180° - 150°∠OPQ = 30°

Answer 2

Answer:

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