Question

PQ is a tangent to a circle with
centre O at point P. If triangle
OPQ is an isoceles triangles Find angle
OPQ ​

Answer 1

Given- O is the centre of a circle to which PQ is a tangent at P. ΔOPQ is isosceles whose vertex is P.

To find out- ∠OQP=?

Solution- OP is a radius through P, the point of contact of the tangent PQ with the given circle ∠OPQ=90

o

since the radius through the point of contact of a tangent to a circle is perpendicular to the tangent. Now ΔOPQ is isosceles whose vertex is P.

∴OP=PQ⟹∠OQP=∠QOP⟹∠OQP+∠QOP=2∠OQP.

∴ By angle sum property of triangles,

∴∠OPQ+2∠OQP=180

o

⟹90

o

+2∠OQP=180

o

⟹∠OQP=45

o

.

solutions

Answer 2

90

Step-by-step explanation:

PQ is tangent so his angle 90