Question

PQ is a tangent to a circle with Centre O touches the circle at point P then angle o p q is​

Answer 1

Answer:

HEY MATE HERE IS YOUR ANSWER,

Step-by-step explanation:

→ ∠QOP + ∠POR = 180°

→ ∠QOP + 120° = 180°

→ ∠QOP = 180° - 120°

→ ∠QOP = 60°

→ In ΔPOQ

→ ∠QOP + ∠OPQ + ∠PQO = 180°

→ 60° + ∠OPQ + 90° = 180°

→ 150° + ∠OPQ = 180

→ ∠OPQ = 180° - 150°

→ ∠OPQ = 30°

thank you

kindly refer the attachment