Question

Pq is diameter of the circle with centre o.angle pqr=65 angle rps=40 & angle pqm=50 find angle qpr,angle prs,qpm angle.

Answer 1

Answer:

Note:In this answer (*) represents degrees.

It is given that: <PQR = 65* ,<RPS = 40* , <PQM = 50*

<QRP = 90* (angle in a semi circle)

So,<QPR = 90* -  65* = 25*

PQRS  is a quadrilateral

So, <PSR = (180* - 65*) = 115*

<PRS = 180* – (115* + 40*) = 25*

<M = 90*,<QPM = 90*– 50* = 40*

I think it helps u..........

Answer 2

Answer:

Step-by-step explanation:

Note:In this answer (*) represents degrees.

It is given that: <PQR = 65* ,<RPS = 40* , <PQM = 50*

<QRP = 90* (angle in a semi circle)

So,<QPR = 90* -  65* = 25*

PQRS  is a quadrilateral

So, <PSR = (180* - 65*) = 115*

<PRS = 180* – (115* + 40*) = 25*

<M = 90*,<QPM = 90*– 50* = 40*