Question

PQ is straight line of 13 units if p has co-ordinates (5,-3)and q has the co-ordinates (-7, y) find the value of y

Answer 1

step by step explanation.

given, PQ = 13 units

here we, apply distance formula

PQ = √(X2-X1)² + (y2-y1)²

squaring on both side.

PQ²=(X2-X1)² + (Y2-Y1)²

13² = (-7 - 5)² + (y- -3)²

169= 144 + y²+9-6y

y²+9-6y + 144 - 169 = 0

y²-6y-16 = 0

y²-8y+2y-16 = 0

y(y-8)+2(y-8)

(y-8) (y+2)

y = 8 or y = -2