Question

PQ is tangent and QR is diameter if angle POR=120⁰ and QR=8cm find OP and PQ​

Answer 1

Answer:

Hope this helps you.

Step-by-step explanation:

∠QOP + ∠POR = 180°

∠QOP + 120° = 180°

∠QOP = 180° - 120°

∠QOP = 60°

In ΔPOQ

∠QOP + ∠OPQ + ∠PQO = 180° 60° + ∠OPQ + 90° = 180° 150° + ∠OPQ = 180°

∠OPQ = 180° - 150°

∠OPQ = 30°