Question

PQ is the diameter of a circle and PR is a chord, if PQ = 34cm and

PR = 30cm. Find the distance of PR from the center of the circle​

Answer 1

Answer:

OX is the perpendicular distance from centre O to the chord AB

∴AX=XB

Now,

AX+XB=AB

⇒2AX=AB

⇒2AX=30

⇒AX= 30/2

⇒AX=15

Again,

AO+OD=AD

⇒2AO=AD

⇒2AO=34

⇒AO=17

△AOX is a right angled triangle

∴(AO ) 2 =(OX ) 2+(AX ) 2

⇒(17 ) 2 =(OX ) 2 +(15 )2

⇒(OX ) 2=(17 ) 2 −(15) 2

⇒(OX) 2 = 64

⇒ OX=8cm