Question

PQ is the diameter of a circle and PR is a chord, if PQ = 34cm and

PR = 30cm. Find the distance of PR from the center of the circle.​

Answer 1

Answer:

OX is the perpendicular distance from centre O to the chord PR

∴PX=XR

Now,

PX+XR=PR

⇒2PX=PR

⇒2PX=30

⇒PX=30/2

⇒PX=15

Again,

PO+OQ=PQ

⇒2PO=PQ

⇒2PO=34

⇒PO=17

△POX is a right angled triangle

2 2 2

∴O =OX + PX

2 2 2

⇒(17 ) = OX +15

2 2 2

⇒OX =17 − 15

2

⇒OX = 64

⇒OX=8cm