Question

PQ is the diameter of a circle and PR is a chord, if PQ = 34cm and

PR = 30cm. Find the distance of PR from the center of the circle.​

Answer 1

Step-by-step explanation:

PQ is the diameter of a circle and PR is a chord, if PQ = 34cm and

OX is the perpendicular distance from centre O to the chord AB

∴AX=XB

Now,

AX+XB=AB

⇒2AX=AB

⇒2AX=30

⇒AX= 2

30

⇒AX=15

Again,

AO+OD=AD

⇒2AO=AD

⇒2AO=34

⇒AO=17

△AOX is a right angled triangle

∴AO 2

=OX2 +AX2

⇒17 2

=OX 2 +15 2

⇒OX 2

=17 2 −15 2

⇒OX 2

= 64

⇒OX=8cm

solution