Question

PQ is the diameter of a circle and PRis chord.If PQ= 50cm,PR= 48cm,then the distance of PR from centre O is
(i)24cm
(ii)25cm
(iii)7cm
(iv)8cm

Answer 1

OKKK I AM FINDING.........

Answer 2

OX is the perpendicular distance from centre O to the chord AB

∴AX=XB

Now,

AX+XB=AB

⇒2AX=AB

⇒2AX=30

⇒AX=

2

30

⇒AX=15

Again,

AO+OD=AD

⇒2AO=AD

⇒2AO=34

⇒AO=17

△AOX is a right angled triangle

∴AO

2

=OX

2

+AX

2

⇒17

2

=OX

2

+15

2

⇒OX

2

=17

2

−15

2

⇒OX

2

=

64

⇒OX=8cm