Question

Pq is the diameter of the circle with centre o and pr is a chord such that

Answer 1

Answer:

Step-by-step explanation:

The question is incomplete

Answer 2

given... AB is the diameter and PQ is the chord of the circle with centre O and AB bisects PQ at R also   PR = RQ = 8 cm and RB = 4 cm

we know that the line from the centre of the circle which bisects the chord is perpendicular to the chord

⇒ AB ⊥ PQ

Let the radius of the circle be r

⇒ OP = OB = r

⇒ OR + RB = r

⇒ OR = r – RB = r-4

Now in right ∆ ORP

OR²+PR²=OP²

⇒ (r – 4)²+8²=R²

⇒r²+4²-2*4*r+64=r²

⇒16-8r+64=0

⇒8r=80

⇒r=80/8

⇒r=10

∴RADIUS 10

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