pq parellel to oq
plz help me
i will mark the first answer as brainlist and do it in correct way
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In ΔPOQ, we have
DE∥OQ(Given)
By Basic proportionality Theorem, we have
EQ
PE
=
DO
PD
…(i)
Similarly,
In ΔPOR, we have
DF∥OR(Given)
∴
DO
PD
=
FR
PF
…(ii)
Now, from (i) and (ii), we have
EQ
PE
=
FR
PF
⇒EF∥QR
[Applying the converse of Basic proportionality Theorem in ΔPQR]
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Step-by-step explanation:
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