Question

PQ perpendicular to PS PO parallel to SR , LSQR = 29 " and LORT = 67 ' , then find the values of and y​

Answer 1

Answer:

if PQ is parallel to SR and QR is a transversal

so, angle PQR=QRT (by alternate interior angle)

PQR=PQS+SQR=QRT

hence,x+29°=67°

x=67°-29°

x=38°

In right angle triangle PQS

sum of all angles of triangle is 180°

so,90°+x+y=180°

90°+38°+y=180°(x=38°)

y=180°-128°

y=52°

hence, the value of x and y is 38° and 52° respectively.