PQ : QR = 3:4
QR : RS
Find PQ : QR : RS ?
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The number of triangles with vertices on side, AB,BC,CD=3C
1
×4C
1
×5C
1
∴ Total no. of triangles =3C
1
×4C
1
×5C
1
+3C
1
×4C
1
×6C
1
+3C
1
×5C
1
×6C
1
+4C
1
×5C
1
×6C
1
=3×4×5+3×4×6+3×5×6+4×5×6
=342
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