Math, asked by raju9rayudu, 2 months ago

(pq+ qr)(pq-qr+pr) -(pr-pq)(p-q-r)​

Answers

Answered by ankitasanwal450
3

Answer:

(pq -qr +pr)(pq+qr)-(pr+pq)(p+q-r)

=p²q²+pq²r-pq²r -q²r²+p²qr +pqr² —p²r-pqr+pr² -p²q- pq²+pqr

=(pq)²-(qr)²+ p²qr+ pqr²- p²r- pr²-p²q- pq²

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