pq+qr+rp+ when p+q+r =√17 and p²+q²+r²=9
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Answered by
6
Solution
(p+q+r)²=p²+q²+r²+2(pq+qr+pr)
=>(√17)²=9+2(pq+qr+pr)
=>(17-9)/2=pq+qr+pr
=>pq+qr+pr=4
Answered by
3
(P+q+r)²= (p²+q²+r²) + 2(pq+qr+rp)
(√17)² = 9 + 2(pq +qr+ rp)
17-9= 2(pq+qr+rp)
8/2= pq+qr+rp
:. Pq+qr+rp= 4
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