Question

pq+qr+rp+ when p+q+r =√17 and p²+q²+r²=9​

Answer 1

Solution

(p+q+r)²=p²+q²+r²+2(pq+qr+pr)

=>(√17)²=9+2(pq+qr+pr)

=>(17-9)/2=pq+qr+pr

=>pq+qr+pr=4

Answer 2

(P+q+r)²= (p²+q²+r²) + 2(pq+qr+rp)

(√17)² = 9 + 2(pq +qr+ rp)

17-9= 2(pq+qr+rp)

8/2= pq+qr+rp

:. Pq+qr+rp= 4

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