pq-rs=7, pqrs=5, then p²q²-r²s²=?
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Step-by-step explanation:
pq-rs=7, pqrs=5 , this is similar to
a - b = 7, ab = 5
so,
(a-b)² = a²+b²-2ab
(7)² = a²+b²-2(5)
49 = a²+b²-10
a²+b² = 59
now substitute,
(PQ)²- (rs)² = 59
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