Question

PQ||RS ABP= 130° ACB= 40°. FIND BAC,RAB,SAC​

Answer 1

Answer:

∠RAB = 180°-130°                          (Sum of interior angles are 180°)

          = 50°

∠SAC = 40°                                   (Alternate interior angles are equal)

∠BAC = 180° - ∠SAC + ∠RAB       (Angles on a straight line is 180°)

          = 180° - 40° + 50°

          = 180° - 90°

          = 90°

Answer 2

Answer:

IF ABP =ACB =40°. BAC =40° RAB IS 130° sac30°