PQ=RS and <ORS =48 THEN <OPQ AND <ROS IS?
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In triangle r o s
os =or(radius of circle)
therefore angle osr=angle ORS
so
48+48+angle sor=180(angle sum property)
angle s o r =180-96
angle s o r=84degree
similarly in triangle poq
angle qop=48degree(pq=rs. and equal arcs substand equal angle)
qo=po(radius)
hence angle qpo also equal to 84 degree
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