(pq+rt)²-2pqrt
solve the question with identity
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As we know that
(a+ b)^2 - 2ab = a^2 + b^2.
And ,
a = pq and b = rt.
So, (pq+rt)²-2pqrt =
(pq)^2 + (rt)^2+2pqrt -2pqrt i.e. p^2 q^2 + r^2 t^2.
Hope you will find it helpful....
Mark it as brainliest.
(a+ b)^2 - 2ab = a^2 + b^2.
And ,
a = pq and b = rt.
So, (pq+rt)²-2pqrt =
(pq)^2 + (rt)^2+2pqrt -2pqrt i.e. p^2 q^2 + r^2 t^2.
Hope you will find it helpful....
Mark it as brainliest.
ansh85:
thanks
please give me answer step by step
it is already in steps....
ask if you have any doubt
Answered by
0
This is not full answer but you have to solve bracket one first and then * by 2.....?
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it's wrong
answer is p²q²+r²t²
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