Question

PQ =x²-5x+6 will be ​

Answer 1

$\huge\tt{\bold{\underline{\underline{Question᎓}}}}$PQ =x²-5x+6 will be

$\huge\tt{\bold{\underline{\underline{Answer᎓}}}}$

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$= > PQ= {x}^{2} - 5x + 6 = 0$

=>It is in the form of a quadratic equation so we factorise it.

=>In factorisation we use middle term splitting method in which we split or divide into two factors the middle value in which we mutiply the coefficient of x^2 with constant ...(1)and place a value in middle in such a manner that addition /subtraction of it makes a middle value (before splitting middle value )and it's product makes a value of Equation1

$= > PQ= {x}^{2} - 6x + x + 6 = 0$

$= > PQ= x(x - 6) - 1(x - 6) = 0$

$\bold{\boxed{ pq = (x - 1)(x - 6) = 0}}$

$(x - 1) = 0$

$=>x = 1$

$(x - 6) = 0$

$=>x = 6$

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Answer 2

Answer:

by splitting a middle term we get

x2-6x+1x+6

x(x-6)-1(x-6)

(x-1)(x-6)

(x=1)(x=6)