Math, asked by narolalemtur73, 1 month ago

(Pq²-p²q) (2p+1):p=-1 and q=2

Answers

Answered by thelaughingoshow
0

Answer:

P

3

−P

2

Q=Q

3

−Q

2

P

⇒P

2

(P−Q)+Q

2

(P−Q)=0

⇒(P

2

+Q

2

)(P−Q)=0

If ∣P

2

+Q

2

=0; then P

2

+Q

2

is invertible

⇒P−Q=0, contradiction

∴∣P

2

+Q

2

∣=0

Answered by LilyWhite
2

Step-by-step explanation:

  • (pq² - p²q) (2p + 1)
  • [ (-1*2)² - (-1)² (2) ] [ (2(-1) + 2) ]
  • [ (-2)² - (1) (2) ] [ (-2) + 2 ]
  • Cancel "-2 & +2"
  • ( 4 - 2 ) ( 0 )
  • 2

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