(Pq²-p²q) (2p+1):p=-1 and q=2
Answers
Answered by
0
Answer:
P
3
−P
2
Q=Q
3
−Q
2
P
⇒P
2
(P−Q)+Q
2
(P−Q)=0
⇒(P
2
+Q
2
)(P−Q)=0
If ∣P
2
+Q
2
∣
=0; then P
2
+Q
2
is invertible
⇒P−Q=0, contradiction
∴∣P
2
+Q
2
∣=0
Answered by
2
Step-by-step explanation:
- (pq² - p²q) (2p + 1)
- [ (-1*2)² - (-1)² (2) ] [ (2(-1) + 2) ]
- [ (-2)² - (1) (2) ] [ (-2) + 2 ]
- Cancel "-2 & +2"
- ( 4 - 2 ) ( 0 )
- 2
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