Pq²+pr²=2(ps²+qs²) in sum (ps) is main
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In △PQR;
PQ=
8
,QR=
5
,PR=
3
(
8
)
2
=8, (
5
)
2
=5, (
3
)
2
=3 and 3+5=8
Thus, the longest length of the sides of the triangle is PQ=8, opposite to ∠R
The square of the largest numbers is equal to the sum of the square of the other two numbers.
∴△PQR form a right-angled triangle, where angle R is of 90
∘
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