pqand pt are tangent to acircle with centre o and radius5cm .if pq 12cm find the parameter of quadrilateral pqot
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As in a circle the tangents from an external point I have equal lengths that gives us :
PQ = PT
But PQ = 12cm
Therefore PT = 12 CM
Now OQ bad OT are the radius of same circle with centre O. Therefore OQ = OT = 5cm
Now perimeter of the quadrilateral formed is :
PQ +PT+OQ+OT= 12+12+5+5
= 24+10 =34cm
Hence the perimeter of quadrilateral PQOT is 34 cm
PQ = PT
But PQ = 12cm
Therefore PT = 12 CM
Now OQ bad OT are the radius of same circle with centre O. Therefore OQ = OT = 5cm
Now perimeter of the quadrilateral formed is :
PQ +PT+OQ+OT= 12+12+5+5
= 24+10 =34cm
Hence the perimeter of quadrilateral PQOT is 34 cm
Answered by
1
Answer:
using pythagoras theorem
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