Question

PQIISR and the bisectors of the interior angles on the same side of the transversal MN intersect at A prove that angle bac=90°​

Answer 1

Step-by-step explanation:

Since AB & AC are angle bisectors

QBA = ABC = (QBC)/2

similarly,

RCA = ACB = (RCB)/2

interior Angles on the same side of the transversal are supplementary angles

so here,

QBC + RCB=180

Dividing by 2 on both sides

=> (QBC)/2 +(RCB)/2= 180/2

=> ABC+ACB= 90.......(1)

In triangle ABC

ABC+ACB +BAC= 180

From (1)___

90+BAC=180

So.. BAC=90

PROVED..

Answer 2

Answer:

hence proved

Step-by-step explanation:

• refer to the attachment..

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