Question

∠PQR =90° and QS⊥PR , if QP = 1.5 cm and QR =2 cm . calculate the length of QS

Answer 1

Answer:

$\huge \pink a \pink n \pink s\pink w \pink e \pink r \over$

Given:-

• PQR = 90°
• QP = 1.5 cm
• QR = 2 cm

To Find:-

• Length of QS

$\huge solution \over$

Area of right angle triangle PQR =

$\frac{1}{2} \times 1.5 \times 2 \: cm \: = 1.5 \: cm \: square$

Right angle triangle = PQ² + QR² = PR²

1.5² + 2² = PR²

2.25 + 4 = PR²

PR=

$\sqrt[6]{2.5}$

PR = 2.5

Area of right triangle PQR =

$\frac{1}{2} \times \frac{1}{215} \times length \times bredth$

$= \frac{1}{2} \times \: pr \times qs \: unit \:square$

$\frac{1}{2} \times 2.5 \times qs \: unit \: square$

$\frac{1}{2} \times 2.5 \times qs = 1.5$

$2.5 \times qs = 1.5 \times 2$

Q5 =

$\frac{3}{2.5}$

Q5 = 1.2