Question

∆PQR =~ ∆ABC. IF PQ=40° & angle P = 80°, calculate the value of C

Refer the photo

Answer 1

the sum of all sides of a triangle is 180°
So angle P + angle Q + angle R= 180°
80°+ 40° + angle R =180°
120° + angle R =180°
angle R= 180°-120°
angle R= 60°
since triangle PQR =~ triangle ABC
Angle C = 60°

Answer 2

pq+p+R=180°
40+80+R=180°
120+R=180°
R=180°-120°
R=60°
now, A/q,
ΔABC =~ΔPQR
so,<R=<C
c=60°