Question

PQR & QST are two right ∆les,at R & T.
Prove that ,
QR×QS=QP×QT

Answer 1

I'm really sorry for the handwriting but hope you'll understand and the solution will be helpful.
Pls mark as brainliest if it helps you....

Answer 2

aloha user!!
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to prove: QR × QS = QP × QT
proof: 

in triangles PQR and SQT 
∠Q = ∠Q  ( COMMON )
∠PRQ = ∠STQ = 90°

SO,

ΔPQR is similar to ΔSQT { by AA similarity criteria }
so, we can write.

$\frac{QR}{QT} = \frac{QP}{QS}$

=> QR × QS = QP × QT
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hope it helps :^)