∆PQR Angle P=90° Angle Q=30° R= x find the value of x
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given angle P=90° and angle Q=30° And angle R=x
Applying angle sum property of a triangle,
angle P +angleQ+AngleR=180°
90°+30°+x=180°
120°+x=180°
x=180°-120°
therefore x=60°
Applying angle sum property of a triangle,
angle P +angleQ+AngleR=180°
90°+30°+x=180°
120°+x=180°
x=180°-120°
therefore x=60°
assassin1111111:
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hope it helps
In triangle PQR
p+q+r=180°
90+30+X=180
then 90 and 30
X=120 -180
X=60
mark me qs brainliest
In triangle PQR
p+q+r=180°
90+30+X=180
then 90 and 30
X=120 -180
X=60
mark me qs brainliest
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