Question

∆PQR , if PQ=10cm, QR= 8cm and PR=6 cm then ,∠R =

pls explain step by step.. pls​

Answer 1

Answer:

90°

Step-by-step explanation:

by Pythagoras Law,

PQ²=PR²+QR²

10²=6²+8²

so in triangle PQR angle R =90°

Answer 2

Answer:

In ∆PQR, ∠R = 90°.

Step-by-step explanation:

According to the concept of sides of triangles, if

• Square of largest side < Sum of squares of other two sides it is an acute angled triangle

• Square of largest side > Sum of squares of other two sides it is an obtuse angled triangle

• Square of largest side = Sum of squares of other two sides it is a right  angled triangle

Applying this in the given question,

$PQ^{2} = QR^{2} +PR^{2}$

$10^{2} = 8^{2} + 6^{2}$

LHS= 100

RHS = 64+36 = 100

LHS= RHS

Therefore, the angle opposite to the largest side makes 90°.

Hence, ∠R = 90°.

The correct answer is ∠R = 90°