Question

PQR is A & S is any point on it prove that SQ+SR<PQ+PR​

Answer 1

In triangle STR

ST + TR > SR.... (i) Sum of two sides of a triangle is greater than the third side.

In triangle PQT

PQ + PT > QT.....(ii) Sum of two sides of a triangle is greater than the third side.

Adding (i) and (ii), we get

ST + TR + PQ + PT > SR + QT

PQ + PR + ST > SR + QS + ST ( PT + TR = PR and QT = QS + ST)

PQ + PR > SQ + SR

RTP:- PQ + PR > SQ + SR

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