PQR is a equilateral triangle and QRST is a square.prove that:- PT=PS angle SR=15 degree
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Since PQRS is a square and ∆ SRT is an equilateral triangle .
:- PST = 90 ° and TSR = 60°
PSR + TSR = 90° + 60°
PST = 150°
Similarly , we have PST and QRT , we have
Thus , in triangles PST and QRT , we have
PS = QR
PST = QRT = 150°
and , ST = RT
So , by SAS congruence criterion , we have
∆ PST ≈ ∆ QRT PT = QT
2) In ∆ TQR , we have
QR = RT
TQR = QTR = x ( say )
Now ,
TQR + QTR + QRT = 180° 2x + 150° = 180° x = 15° .
:- PST = 90 ° and TSR = 60°
PSR + TSR = 90° + 60°
PST = 150°
Similarly , we have PST and QRT , we have
Thus , in triangles PST and QRT , we have
PS = QR
PST = QRT = 150°
and , ST = RT
So , by SAS congruence criterion , we have
∆ PST ≈ ∆ QRT PT = QT
2) In ∆ TQR , we have
QR = RT
TQR = QTR = x ( say )
Now ,
TQR + QTR + QRT = 180° 2x + 150° = 180° x = 15° .
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