PQR is a isosceles right triangle right angled at Q Prove that
![PQ^{2} PQ^{2}](https://tex.z-dn.net/?f=+PQ%5E%7B2%7D+)
=2PQ
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noob
Step-by-step explanation:
jpukRed fof/ µ Nk=kksa n~okjk ijLij laLo`Qr esa laokn vkSj fp=kkaduA d{kk&dk;Z µ ikB esa vk, izFkek&f}rh;k foHkfDr osQ 'kCnksa vkSj fozQ;kinksa dh lkj.kh dk fuekZ.kA x`g&dk;Z µ deZin p;u] ,d 'kCn esa mRrj] 'kCnksa ls okD; jpuk] f}rh;k foHkfDr osQ :iksa dk ys[ku] mfpr&vFkZ&p;u] /kRoFkZ esyu] laLo`QrkuqoknA fu"d"kZ µ Nk=k f}rh;k foHkfDr osQ 'kCnksa dk leqfpr iz;ksx dj ldrs gSaA fujh{k.k µ lHkh fd, x, dk;ks± dk fujh{k.k] ijh{k.k] ewY;kadu] =kqfV la'kks/u] 'kadk lekèkkuA ikBkuqokn Nk=k iqLrd i
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